Hi at all,
I have a doubt about how can I start my app on console ttyO0, these are steps that I follow,
I have edited uEnv.txt
with this line
console=,115200n81 (without ttyO0)
I have try to autologin:
cp /lib/systemd/system/serial-getty@.service /etc/systemd/system/autologin@.service
rm /etc/systemd/system/getty.target.wants/serial-getty@ttyO0.service
ln -s /etc/systemd/system/autologin@.service /etc/systemd/system/getty.target.wants/serial-getty@ttyO0.service
Create the following script file in any location (/home/root/autologin.sh in my case)
#!/bin/sh
exec /bin/login -f root
Make it executable
chmod a+x autologin.sh
Edit /etc/systemd/system/autologin@.service and update the ExecStart command by adding the -n (Do not prompt the user for a login name) and -l (Invoke the specified login_program instead of /bin/login) options.
ExecStart=-/sbin/agetty -n -l /home/root/autologin.sh -s %I 115200
My problem is I can read the output of my APP over console but I can`t write on ttyO0 (console).
Anybody can I help me…thank you.