How to boot up into my own X11 GUI without gdm3

General Discussion
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1

Hi,
Has anyone successfully boot directly into your own GUI with X11 but without using the gdb3 service?

The details:
I created a gui_autoexec.service with type=forking to a separate process that launches the “xinit, gui_app”. It automatically launches the gui_app successfully; but after a few minutes, the application shuts down. The system journal shows the cause is " xinit: unexpected signal"

However, when I launch the X11 and the GUI application directly from the command line, the application runs fine.

I am suspecting that the error in the gui_autoexec.service configuration but I cannot figure out what would be the proper option to run my gui application in a separate process from the gui_autoexec.service (keep the gui_app running after the gui_autoexec.service and its subsequence supporting shell completed. Enclosed is the content of the gui_autoexec.service

[Unit]
Description=Service for GUI Application Loader
After=systemd-user-sessions.service
After=getty@tty1.service

[Service]
Type=forking
RemainAfterExit=true
Restart=on-watchdog

User=debian

#Launch gui appl from a script
ExecStart=/home/debian/bin/auto_load_systemd.sh
WorkingDirectory=/home/debian/bin

[Install]
WantedBy=graphical.target

2

Just use slim and openbox… FLIR Lepton on BeagleBone Black and Green - Linux Guides - Electronic Component and Engineering Solution Forum - TechForum │ DigiKey

Regards,

1 Like
3

I found the solution. It requires an extended timeout which can be done by the changes in the /etc/systemd/system/gui_autoexec.service which shown below. We can close this issue.

[Service]
Type=forking
Restart=no
TimeoutStartSec=300 #in seconds
TimeoutStopSec=infinity